Base | Representation |
---|---|
bin | 11111000001100110111… |
… | …010010010000011001011 |
3 | 21112211010212012201001021 |
4 | 133001212322102003023 |
5 | 234412344231130011 |
6 | 4311235145133311 |
7 | 310014461551006 |
oct | 37014672220313 |
9 | 7484125181037 |
10 | 2132030333131 |
11 | 7522095a5286 |
12 | 2a525078a237 |
13 | 126084c73a4a |
14 | 7529586c53d |
15 | 3a6d41e6471 |
hex | 1f066e920cb |
2132030333131 has 2 divisors, whose sum is σ = 2132030333132. Its totient is φ = 2132030333130.
The previous prime is 2132030333099. The next prime is 2132030333149. The reversal of 2132030333131 is 1313330302312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2132030333131 - 25 = 2132030333099 is a prime.
It is a super-2 number, since 2×21320303331312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2132030333096 and 2132030333105.
It is not a weakly prime, because it can be changed into another prime (2132030333431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066015166565 + 1066015166566.
It is an arithmetic number, because the mean of its divisors is an integer number (1066015166566).
Almost surely, 22132030333131 is an apocalyptic number.
2132030333131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2132030333131 is an equidigital number, since it uses as much as digits as its factorization.
2132030333131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 2132030333131 its reverse (1313330302312), we get a palindrome (3445360635443).
The spelling of 2132030333131 in words is "two trillion, one hundred thirty-two billion, thirty million, three hundred thirty-three thousand, one hundred thirty-one".
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