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213203100212233 is a prime number
BaseRepresentation
bin110000011110100000110111…
…000011011001110000001001
31000221220000110122000101000121
4300132200313003121300021
5210421104422123242413
62033240052504303241
762623262401363645
oct6036406703316011
91027800418011017
10213203100212233
1161a29a2197060a
121bab4232a71b21
1391c6c73636c71
143a9112977bc25
15199ad7de36b8d
hexc1e8370d9c09

213203100212233 has 2 divisors, whose sum is σ = 213203100212234. Its totient is φ = 213203100212232.

The previous prime is 213203100212189. The next prime is 213203100212237. The reversal of 213203100212233 is 332212001302312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 153580426061049 + 59622674151184 = 12392757^2 + 7721572^2 .

It is a cyclic number.

It is not a de Polignac number, because 213203100212233 - 213 = 213203100204041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 213203100212198 and 213203100212207.

It is not a weakly prime, because it can be changed into another prime (213203100212237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106601550106116 + 106601550106117.

It is an arithmetic number, because the mean of its divisors is an integer number (106601550106117).

Almost surely, 2213203100212233 is an apocalyptic number.

It is an amenable number.

213203100212233 is a deficient number, since it is larger than the sum of its proper divisors (1).

213203100212233 is an equidigital number, since it uses as much as digits as its factorization.

213203100212233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 213203100212233 its reverse (332212001302312), we get a palindrome (545415101514545).

The spelling of 213203100212233 in words is "two hundred thirteen trillion, two hundred three billion, one hundred million, two hundred twelve thousand, two hundred thirty-three".