Base | Representation |
---|---|
bin | 1001101100100001101011… |
… | …10111001101000101011111 |
3 | 2210111021112121022020210120 |
4 | 10312100311313031011133 |
5 | 10243311124024240221 |
6 | 113202442105010023 |
7 | 4330254155664450 |
oct | 466206567150537 |
9 | 83437477266716 |
10 | 21321121321311 |
11 | 6880267166579 |
12 | 2484214483913 |
13 | bb875b190426 |
14 | 539d3a9bb127 |
15 | 26e9281c05c6 |
hex | 136435dcd15f |
21321121321311 has 16 divisors (see below), whose sum is σ = 34199292345600. Its totient is φ = 11542261166208.
The previous prime is 21321121321303. The next prime is 21321121321369. The reversal of 21321121321311 is 11312312112312.
It is not a de Polignac number, because 21321121321311 - 23 = 21321121321303 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21321121321411) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26718196746 + ... + 26718197543.
It is an arithmetic number, because the mean of its divisors is an integer number (2137455771600).
Almost surely, 221321121321311 is an apocalyptic number.
21321121321311 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
21321121321311 is a deficient number, since it is larger than the sum of its proper divisors (12878171024289).
21321121321311 is a wasteful number, since it uses less digits than its factorization.
21321121321311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53436394318.
The product of its digits is 432, while the sum is 24.
Adding to 21321121321311 its reverse (11312312112312), we get a palindrome (32633433433623).
The spelling of 21321121321311 in words is "twenty-one trillion, three hundred twenty-one billion, one hundred twenty-one million, three hundred twenty-one thousand, three hundred eleven".
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