Base | Representation |
---|---|
bin | 11111000001101101000… |
… | …101101111111001000001 |
3 | 21112211102002021122022221 |
4 | 133001231011233321001 |
5 | 234413102301032431 |
6 | 4311253331131041 |
7 | 310020160664215 |
oct | 37015505577101 |
9 | 7484362248287 |
10 | 2132134002241 |
11 | 752262072431 |
12 | 2a527b443a81 |
13 | 1260a05a0609 |
14 | 752a5536945 |
15 | 3a6dd373111 |
hex | 1f06d16fe41 |
2132134002241 has 4 divisors (see below), whose sum is σ = 2132163965952. Its totient is φ = 2132104038532.
The previous prime is 2132134002217. The next prime is 2132134002253. The reversal of 2132134002241 is 1422004312312.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2132134002241 - 29 = 2132134001729 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2132134002041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14874865 + ... + 15017518.
It is an arithmetic number, because the mean of its divisors is an integer number (533040991488).
Almost surely, 22132134002241 is an apocalyptic number.
It is an amenable number.
2132134002241 is a deficient number, since it is larger than the sum of its proper divisors (29963711).
2132134002241 is an equidigital number, since it uses as much as digits as its factorization.
2132134002241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29963710.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2132134002241 its reverse (1422004312312), we get a palindrome (3554138314553).
The spelling of 2132134002241 in words is "two trillion, one hundred thirty-two billion, one hundred thirty-four million, two thousand, two hundred forty-one".
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