Base | Representation |
---|---|
bin | 11111000001101101011… |
… | …101011110100000010001 |
3 | 21112211102111222122220012 |
4 | 133001231131132200101 |
5 | 234413110344104411 |
6 | 4311254112324305 |
7 | 310020264602063 |
oct | 37015535364021 |
9 | 7484374878805 |
10 | 2132140222481 |
11 | 752265630825 |
12 | 2a5281543695 |
13 | 1260a196a929 |
14 | 752a62b5733 |
15 | 3a6ddba118b |
hex | 1f06d75e811 |
2132140222481 has 2 divisors, whose sum is σ = 2132140222482. Its totient is φ = 2132140222480.
The previous prime is 2132140222369. The next prime is 2132140222549. The reversal of 2132140222481 is 1842220412312.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1127013668881 + 1005126553600 = 1061609^2 + 1002560^2 .
It is a cyclic number.
It is not a de Polignac number, because 2132140222481 - 238 = 1857262315537 is a prime.
It is a super-2 number, since 2×21321402224812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2132140222781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066070111240 + 1066070111241.
It is an arithmetic number, because the mean of its divisors is an integer number (1066070111241).
Almost surely, 22132140222481 is an apocalyptic number.
It is an amenable number.
2132140222481 is a deficient number, since it is larger than the sum of its proper divisors (1).
2132140222481 is an equidigital number, since it uses as much as digits as its factorization.
2132140222481 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12288, while the sum is 32.
Adding to 2132140222481 its reverse (1842220412312), we get a palindrome (3974360634793).
The spelling of 2132140222481 in words is "two trillion, one hundred thirty-two billion, one hundred forty million, two hundred twenty-two thousand, four hundred eighty-one".
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