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213221311441 is a prime number
BaseRepresentation
bin1100011010010011111…
…0110000001111010001
3202101100202111220011221
43012210332300033101
511443134123431231
6241541424405041
721255552146335
oct3064476601721
9671322456157
10213221311441
1182476965176
12353a7476781
13171504ca498
14a469db97c5
15582e03ed11
hex31a4fb03d1

213221311441 has 2 divisors, whose sum is σ = 213221311442. Its totient is φ = 213221311440.

The previous prime is 213221311361. The next prime is 213221311463. The reversal of 213221311441 is 144113122312.

213221311441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 166236413841 + 46984897600 = 407721^2 + 216760^2 .

It is a cyclic number.

It is not a de Polignac number, because 213221311441 - 211 = 213221309393 is a prime.

It is not a weakly prime, because it can be changed into another prime (213221315441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106610655720 + 106610655721.

It is an arithmetic number, because the mean of its divisors is an integer number (106610655721).

Almost surely, 2213221311441 is an apocalyptic number.

It is an amenable number.

213221311441 is a deficient number, since it is larger than the sum of its proper divisors (1).

213221311441 is an equidigital number, since it uses as much as digits as its factorization.

213221311441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1152, while the sum is 25.

Adding to 213221311441 its reverse (144113122312), we get a palindrome (357334433753).

The spelling of 213221311441 in words is "two hundred thirteen billion, two hundred twenty-one million, three hundred eleven thousand, four hundred forty-one".