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21323130040114 = 272217582959593
BaseRepresentation
bin1001101100100101011011…
…00101110110111100110010
32210111110201121001201222021
410312102231211312330302
510243324232242240424
6113203413302502054
74330355016551500
oct466225545667462
983443647051867
1021323130040114
1168810a8018761
12248469513492a
13bb89bb39b136
1453a08b6a5670
1526e9e47064e4
hex1364ad976f32

21323130040114 has 12 divisors (see below), whose sum is σ = 37206686090574. Its totient is φ = 9138484302864.

The previous prime is 21323130040099. The next prime is 21323130040133. The reversal of 21323130040114 is 41104003132312.

It can be written as a sum of positive squares in only one way, i.e., 17903755826089 + 3419374214025 = 4231283^2 + 1849155^2 .

It is a super-2 number, since 2×213231300401142 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 108791479699 + ... + 108791479894.

Almost surely, 221323130040114 is an apocalyptic number.

21323130040114 is a deficient number, since it is larger than the sum of its proper divisors (15883556050460).

21323130040114 is a wasteful number, since it uses less digits than its factorization.

21323130040114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 217582959609 (or 217582959602 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 21323130040114 its reverse (41104003132312), we get a palindrome (62427133172426).

The spelling of 21323130040114 in words is "twenty-one trillion, three hundred twenty-three billion, one hundred thirty million, forty thousand, one hundred fourteen".

Divisors: 1 2 7 14 49 98 217582959593 435165919186 1523080717151 3046161434302 10661565020057 21323130040114