Base | Representation |
---|---|
bin | 110000011110111011001011… |
… | …000000101101111101001011 |
3 | 1000221222201101120101011212011 |
4 | 300132323023000231331023 |
5 | 210422040302144342144 |
6 | 2033301044141400351 |
7 | 62625312455455156 |
oct | 6036731300557513 |
9 | 1027881346334764 |
10 | 213231352340299 |
11 | 61a3a9aa514587 |
12 | 1bab97b85690b7 |
13 | 91c9826860bc7 |
14 | 3a926499dcc9d |
15 | 199b9843a2a34 |
hex | c1eecb02df4b |
213231352340299 has 2 divisors, whose sum is σ = 213231352340300. Its totient is φ = 213231352340298.
The previous prime is 213231352340291. The next prime is 213231352340333. The reversal of 213231352340299 is 992043253132312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213231352340299 - 23 = 213231352340291 is a prime.
It is not a weakly prime, because it can be changed into another prime (213231352340291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106615676170149 + 106615676170150.
It is an arithmetic number, because the mean of its divisors is an integer number (106615676170150).
Almost surely, 2213231352340299 is an apocalyptic number.
213231352340299 is a deficient number, since it is larger than the sum of its proper divisors (1).
213231352340299 is an equidigital number, since it uses as much as digits as its factorization.
213231352340299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2099520, while the sum is 49.
The spelling of 213231352340299 in words is "two hundred thirteen trillion, two hundred thirty-one billion, three hundred fifty-two million, three hundred forty thousand, two hundred ninety-nine".
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