Base | Representation |
---|---|
bin | 1100011010010110100… |
… | …1001011101111001001 |
3 | 202101101112102222122001 |
4 | 3012211221023233021 |
5 | 11443200000342441 |
6 | 241542503031001 |
7 | 21256045533100 |
oct | 3064551135711 |
9 | 671345388561 |
10 | 213232434121 |
11 | 82482171873 |
12 | 353ab13b461 |
13 | 171528c3055 |
14 | a46b673037 |
15 | 582eeda731 |
hex | 31a5a4bbc9 |
213232434121 has 24 divisors (see below), whose sum is σ = 250536297024. Its totient is φ = 180936796320.
The previous prime is 213232434097. The next prime is 213232434139. The reversal of 213232434121 is 121434232312.
It is not a de Polignac number, because 213232434121 - 211 = 213232432073 is a prime.
It is a super-2 number, since 2×2132324341212 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 213232434121.
It is not an unprimeable number, because it can be changed into a prime (213232434161) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 22822911 + ... + 22832251.
It is an arithmetic number, because the mean of its divisors is an integer number (10439012376).
Almost surely, 2213232434121 is an apocalyptic number.
It is an amenable number.
213232434121 is a deficient number, since it is larger than the sum of its proper divisors (37303862903).
213232434121 is a wasteful number, since it uses less digits than its factorization.
213232434121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13981 (or 13974 counting only the distinct ones).
The product of its digits is 6912, while the sum is 28.
Adding to 213232434121 its reverse (121434232312), we get a palindrome (334666666433).
The spelling of 213232434121 in words is "two hundred thirteen billion, two hundred thirty-two million, four hundred thirty-four thousand, one hundred twenty-one".
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