Base | Representation |
---|---|
bin | 1100011010011000101… |
… | …1100000010100001011 |
3 | 202101102011101002110011 |
4 | 3012212023200110023 |
5 | 11443204301300212 |
6 | 241543423532351 |
7 | 21256215155002 |
oct | 3064613402413 |
9 | 671364332404 |
10 | 213241431307 |
11 | 82487257563 |
12 | 353b215a0b7 |
13 | 17154723328 |
14 | a46c935c39 |
15 | 5830bb64a7 |
hex | 31a62e050b |
213241431307 has 2 divisors, whose sum is σ = 213241431308. Its totient is φ = 213241431306.
The previous prime is 213241431301. The next prime is 213241431329. The reversal of 213241431307 is 703134142312.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-213241431307 is a prime.
It is not a weakly prime, because it can be changed into another prime (213241431301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106620715653 + 106620715654.
It is an arithmetic number, because the mean of its divisors is an integer number (106620715654).
Almost surely, 2213241431307 is an apocalyptic number.
213241431307 is a deficient number, since it is larger than the sum of its proper divisors (1).
213241431307 is an equidigital number, since it uses as much as digits as its factorization.
213241431307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 213241431307 its reverse (703134142312), we get a palindrome (916375573619).
The spelling of 213241431307 in words is "two hundred thirteen billion, two hundred forty-one million, four hundred thirty-one thousand, three hundred seven".
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