Base | Representation |
---|---|
bin | 11111000001111101110… |
… | …011111011101000111011 |
3 | 21112212010122011122212212 |
4 | 133001331303323220323 |
5 | 234414141110410233 |
6 | 4311341232125335 |
7 | 310030135363421 |
oct | 37017563735073 |
9 | 7485118148785 |
10 | 2132414544443 |
11 | 752396466997 |
12 | 2a533939684b |
13 | 126116747a11 |
14 | 752d08c3111 |
15 | 3a707cdba48 |
hex | 1f07dcfba3b |
2132414544443 has 2 divisors, whose sum is σ = 2132414544444. Its totient is φ = 2132414544442.
The previous prime is 2132414544433. The next prime is 2132414544461. The reversal of 2132414544443 is 3444454142312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2132414544443 - 24 = 2132414544427 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2132414544443.
It is not a weakly prime, because it can be changed into another prime (2132414544433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066207272221 + 1066207272222.
It is an arithmetic number, because the mean of its divisors is an integer number (1066207272222).
Almost surely, 22132414544443 is an apocalyptic number.
2132414544443 is a deficient number, since it is larger than the sum of its proper divisors (1).
2132414544443 is an equidigital number, since it uses as much as digits as its factorization.
2132414544443 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 737280, while the sum is 41.
Adding to 2132414544443 its reverse (3444454142312), we get a palindrome (5576868686755).
The spelling of 2132414544443 in words is "two trillion, one hundred thirty-two billion, four hundred fourteen million, five hundred forty-four thousand, four hundred forty-three".
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