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213244134113 = 647329589079
BaseRepresentation
bin1100011010011001010…
…1110100001011100001
3202101102100110102000002
43012212111310023201
511443210444242423
6241544001505345
721256250142623
oct3064625641341
9671370412002
10213244134113
118248883318a
12353b3042255
131715515b61a
14a46d03ac13
15583104c228
hex31a65742e1

213244134113 has 4 divisors (see below), whose sum is σ = 213573723840. Its totient is φ = 212914544388.

The previous prime is 213244134073. The next prime is 213244134119. The reversal of 213244134113 is 311431442312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 213244134113 - 26 = 213244134049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (213244134119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 164793893 + ... + 164795186.

It is an arithmetic number, because the mean of its divisors is an integer number (53393430960).

Almost surely, 2213244134113 is an apocalyptic number.

It is an amenable number.

213244134113 is a deficient number, since it is larger than the sum of its proper divisors (329589727).

213244134113 is an equidigital number, since it uses as much as digits as its factorization.

213244134113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 329589726.

The product of its digits is 6912, while the sum is 29.

Adding to 213244134113 its reverse (311431442312), we get a palindrome (524675576425).

The spelling of 213244134113 in words is "two hundred thirteen billion, two hundred forty-four million, one hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 647 329589079 213244134113