Base | Representation |
---|---|
bin | 1001101100110010110110… |
… | …11010101011011010000011 |
3 | 2210112011100011100022111001 |
4 | 10312121123122223122003 |
5 | 10243434014333442011 |
6 | 113211005025232431 |
7 | 4331031512423245 |
oct | 466313332533203 |
9 | 83464304308431 |
10 | 21330341312131 |
11 | 68841686540a5 |
12 | 2485b68192717 |
13 | bb959a3a6bb7 |
14 | 53a5732da095 |
15 | 26ecb78547c1 |
hex | 13665b6ab683 |
21330341312131 has 2 divisors, whose sum is σ = 21330341312132. Its totient is φ = 21330341312130.
The previous prime is 21330341312101. The next prime is 21330341312171. The reversal of 21330341312131 is 13121314303312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21330341312131 - 219 = 21330340787843 is a prime.
It is a super-2 number, since 2×213303413121312 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 21330341312131.
It is not a weakly prime, because it can be changed into another prime (21330341312101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10665170656065 + 10665170656066.
It is an arithmetic number, because the mean of its divisors is an integer number (10665170656066).
Almost surely, 221330341312131 is an apocalyptic number.
21330341312131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21330341312131 is an equidigital number, since it uses as much as digits as its factorization.
21330341312131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 28.
Adding to 21330341312131 its reverse (13121314303312), we get a palindrome (34451655615443).
The spelling of 21330341312131 in words is "twenty-one trillion, three hundred thirty billion, three hundred forty-one million, three hundred twelve thousand, one hundred thirty-one".
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