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213304003153 is a prime number
BaseRepresentation
bin1100011010100111101…
…0001100101001010001
3202101120112010001212221
43012221322030221101
511443321311100103
6241553541021041
721260605053133
oct3065172145121
9671515101787
10213304003153
118250960472a
123540b0b4781
1317164690aa7
14a476d83053
1558364261bd
hex31a9e8ca51

213304003153 has 2 divisors, whose sum is σ = 213304003154. Its totient is φ = 213304003152.

The previous prime is 213304003147. The next prime is 213304003163. The reversal of 213304003153 is 351300403312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 133409023504 + 79894979649 = 365252^2 + 282657^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-213304003153 is a prime.

It is a super-2 number, since 2×2133040031532 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (213304003163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106652001576 + 106652001577.

It is an arithmetic number, because the mean of its divisors is an integer number (106652001577).

Almost surely, 2213304003153 is an apocalyptic number.

It is an amenable number.

213304003153 is a deficient number, since it is larger than the sum of its proper divisors (1).

213304003153 is an equidigital number, since it uses as much as digits as its factorization.

213304003153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3240, while the sum is 25.

Adding to 213304003153 its reverse (351300403312), we get a palindrome (564604406465).

The spelling of 213304003153 in words is "two hundred thirteen billion, three hundred four million, three thousand, one hundred fifty-three".