Base | Representation |
---|---|
bin | 110000100000000110011000… |
… | …110010011101110111100001 |
3 | 1000222021102211222220210011221 |
4 | 300200012120302131313201 |
5 | 210424401202203402314 |
6 | 2033402122110535041 |
7 | 62634202020336244 |
oct | 6040063062356741 |
9 | 1028242758823157 |
10 | 213312114122209 |
11 | 61a71183428693 |
12 | 1bb11397507481 |
13 | 920432775713b |
14 | 3a9650b9d525b |
15 | 199db0e699824 |
hex | c20198c9dde1 |
213312114122209 has 2 divisors, whose sum is σ = 213312114122210. Its totient is φ = 213312114122208.
The previous prime is 213312114122197. The next prime is 213312114122257. The reversal of 213312114122209 is 902221411213312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 175381604621584 + 37930509500625 = 13243172^2 + 6158775^2 .
It is a cyclic number.
It is not a de Polignac number, because 213312114122209 - 213 = 213312114114017 is a prime.
It is not a weakly prime, because it can be changed into another prime (213312114123209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106656057061104 + 106656057061105.
It is an arithmetic number, because the mean of its divisors is an integer number (106656057061105).
Almost surely, 2213312114122209 is an apocalyptic number.
It is an amenable number.
213312114122209 is a deficient number, since it is larger than the sum of its proper divisors (1).
213312114122209 is an equidigital number, since it uses as much as digits as its factorization.
213312114122209 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 34.
The spelling of 213312114122209 in words is "two hundred thirteen trillion, three hundred twelve billion, one hundred fourteen million, one hundred twenty-two thousand, two hundred nine".
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