Base | Representation |
---|---|
bin | 11111000010101000001… |
… | …110011100001010111011 |
3 | 21112220222020011021200111 |
4 | 133002220032130022323 |
5 | 234422120242332012 |
6 | 4311540012045151 |
7 | 310053565665022 |
oct | 37025016341273 |
9 | 7486866137614 |
10 | 2133126136507 |
11 | 752721103603 |
12 | 2a54b77637b7 |
13 | 1261cacb5502 |
14 | 7535b1d78b9 |
15 | 3a74a4edba7 |
hex | 1f0a839c2bb |
2133126136507 has 2 divisors, whose sum is σ = 2133126136508. Its totient is φ = 2133126136506.
The previous prime is 2133126136501. The next prime is 2133126136601. The reversal of 2133126136507 is 7056316213312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2133126136507 - 215 = 2133126103739 is a prime.
It is a super-2 number, since 2×21331261365072 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2133126136507.
It is not a weakly prime, because it can be changed into another prime (2133126136501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066563068253 + 1066563068254.
It is an arithmetic number, because the mean of its divisors is an integer number (1066563068254).
Almost surely, 22133126136507 is an apocalyptic number.
2133126136507 is a deficient number, since it is larger than the sum of its proper divisors (1).
2133126136507 is an equidigital number, since it uses as much as digits as its factorization.
2133126136507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 136080, while the sum is 40.
The spelling of 2133126136507 in words is "two trillion, one hundred thirty-three billion, one hundred twenty-six million, one hundred thirty-six thousand, five hundred seven".
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