Base | Representation |
---|---|
bin | 1001101100110100101010… |
… | …01110111011100111101011 |
3 | 2210112020211202120101020122 |
4 | 10312122111032323213223 |
5 | 10243443011143430324 |
6 | 113211245155513455 |
7 | 4331064531323261 |
oct | 466322516734753 |
9 | 83466752511218 |
10 | 21331311311339 |
11 | 6884616146937 |
12 | 2486198bb888b |
13 | bb96c333b923 |
14 | 53a626078431 |
15 | 26ed22aaba5e |
hex | 1366953bb9eb |
21331311311339 has 2 divisors, whose sum is σ = 21331311311340. Its totient is φ = 21331311311338.
The previous prime is 21331311311333. The next prime is 21331311311347. The reversal of 21331311311339 is 93311311313312.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21331311311339 is a prime.
It is a super-2 number, since 2×213313113113392 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21331311311299 and 21331311311308.
It is not a weakly prime, because it can be changed into another prime (21331311311333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10665655655669 + 10665655655670.
It is an arithmetic number, because the mean of its divisors is an integer number (10665655655670).
Almost surely, 221331311311339 is an apocalyptic number.
21331311311339 is a deficient number, since it is larger than the sum of its proper divisors (1).
21331311311339 is an equidigital number, since it uses as much as digits as its factorization.
21331311311339 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 13122, while the sum is 35.
The spelling of 21331311311339 in words is "twenty-one trillion, three hundred thirty-one billion, three hundred eleven million, three hundred eleven thousand, three hundred thirty-nine".
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