Base | Representation |
---|---|
bin | 11111000010110011001… |
… | …100000100011000010011 |
3 | 21112221110001020202222022 |
4 | 133002303030010120103 |
5 | 234423004334023042 |
6 | 4312010142202055 |
7 | 310061261232143 |
oct | 37026314043023 |
9 | 7487401222868 |
10 | 2133310064147 |
11 | 752805a09119 |
12 | 2a554928332b |
13 | 12622a133032 |
14 | 753777d4923 |
15 | 3a75b730cd2 |
hex | 1f0b3304613 |
2133310064147 has 2 divisors, whose sum is σ = 2133310064148. Its totient is φ = 2133310064146.
The previous prime is 2133310064077. The next prime is 2133310064161. The reversal of 2133310064147 is 7414600133312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2133310064147 - 212 = 2133310060051 is a prime.
It is not a weakly prime, because it can be changed into another prime (2133310064647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066655032073 + 1066655032074.
It is an arithmetic number, because the mean of its divisors is an integer number (1066655032074).
Almost surely, 22133310064147 is an apocalyptic number.
2133310064147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2133310064147 is an equidigital number, since it uses as much as digits as its factorization.
2133310064147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36288, while the sum is 35.
Adding to 2133310064147 its reverse (7414600133312), we get a palindrome (9547910197459).
The spelling of 2133310064147 in words is "two trillion, one hundred thirty-three billion, three hundred ten million, sixty-four thousand, one hundred forty-seven".
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