Base | Representation |
---|---|
bin | 11111000010110011011… |
… | …000011101110011100001 |
3 | 21112221110021100212221212 |
4 | 133002303120131303201 |
5 | 234423011202022032 |
6 | 4312010335555505 |
7 | 310061330656034 |
oct | 37026330356341 |
9 | 7487407325855 |
10 | 2133313314017 |
11 | 752807828866 |
12 | 2a554a38bb95 |
13 | 12622aa00332 |
14 | 75377ddd01b |
15 | 3a75bb73bb2 |
hex | 1f0b361dce1 |
2133313314017 has 2 divisors, whose sum is σ = 2133313314018. Its totient is φ = 2133313314016.
The previous prime is 2133313313987. The next prime is 2133313314131. The reversal of 2133313314017 is 7104133133312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2014699198801 + 118614115216 = 1419401^2 + 344404^2 .
It is a cyclic number.
It is not a de Polignac number, because 2133313314017 - 216 = 2133313248481 is a prime.
It is not a weakly prime, because it can be changed into another prime (2133313314817) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066656657008 + 1066656657009.
It is an arithmetic number, because the mean of its divisors is an integer number (1066656657009).
Almost surely, 22133313314017 is an apocalyptic number.
It is an amenable number.
2133313314017 is a deficient number, since it is larger than the sum of its proper divisors (1).
2133313314017 is an equidigital number, since it uses as much as digits as its factorization.
2133313314017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13608, while the sum is 32.
Adding to 2133313314017 its reverse (7104133133312), we get a palindrome (9237446447329).
The spelling of 2133313314017 in words is "two trillion, one hundred thirty-three billion, three hundred thirteen million, three hundred fourteen thousand, seventeen".
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