213333123314433 has 4 divisors (see below), whose sum is σ = 284444164419248. Its totient is φ = 142222082209620.

The previous prime is 213333123314429. The next prime is 213333123314557. The reversal of 213333123314433 is 334413321333312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 213333123314433 - 2² = 213333123314429 is a prime.

It is a super-2 number, since 2×213333123314433² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 213333123314391 and 213333123314400.

It is not an unprimeable number, because it can be changed into a prime (213333123314033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35555520552403 + ... + 35555520552408.

It is an arithmetic number, because the mean of its divisors is an integer number (71111041104812).

Almost surely, 2^{213333123314433} is an apocalyptic number.

It is an amenable number.

213333123314433 is a deficient number, since it is larger than the sum of its proper divisors (71111041104815).

213333123314433 is an equidigital number, since it uses as much as digits as its factorization.

213333123314433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71111041104814.

The product of its digits is 419904, while the sum is 39.

Adding to 213333123314433 its reverse (334413321333312), we get a palindrome (547746444647745).

The spelling of 213333123314433 in words is "two hundred thirteen trillion, three hundred thirty-three billion, one hundred twenty-three million, three hundred fourteen thousand, four hundred thirty-three".