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213334345651 = 7121325124761
BaseRepresentation
bin1100011010101110110…
…1111100011110110011
3202101122122012121222011
43012223231330132303
511443402043030101
6242000543223351
721261424006210
oct3065355743663
9671578177864
10213334345651
1182524749479
12354192a7b57
131716aa5592b
14a47b000b07
155838e1b751
hex31abb7c7b3

213334345651 has 8 divisors (see below), whose sum is σ = 244011688544. Its totient is φ = 182707254720.

The previous prime is 213334345621. The next prime is 213334345661. The reversal of 213334345651 is 156543433312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 213334345651 - 211 = 213334343603 is a prime.

It is a super-2 number, since 2×2133343456512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (213334345621) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12553890 + ... + 12570871.

It is an arithmetic number, because the mean of its divisors is an integer number (30501461068).

Almost surely, 2213334345651 is an apocalyptic number.

213334345651 is a deficient number, since it is larger than the sum of its proper divisors (30677342893).

213334345651 is a wasteful number, since it uses less digits than its factorization.

213334345651 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25125981.

The product of its digits is 388800, while the sum is 40.

Adding to 213334345651 its reverse (156543433312), we get a palindrome (369877778963).

The spelling of 213334345651 in words is "two hundred thirteen billion, three hundred thirty-four million, three hundred forty-five thousand, six hundred fifty-one".

Divisors: 1 7 1213 8491 25124761 175873327 30476335093 213334345651