Base | Representation |
---|---|
bin | 11111000010111011000… |
… | …111010111111010010001 |
3 | 21112221210022111012211222 |
4 | 133002323013113322101 |
5 | 234423242410114103 |
6 | 4312031252414425 |
7 | 310064464503311 |
oct | 37027307277221 |
9 | 7487708435758 |
10 | 2133443051153 |
11 | 752873a90237 |
12 | 2a5585917415 |
13 | 12624b85627b |
14 | 7538b331441 |
15 | 3a76824e638 |
hex | 1f0bb1d7e91 |
2133443051153 has 2 divisors, whose sum is σ = 2133443051154. Its totient is φ = 2133443051152.
The previous prime is 2133443051119. The next prime is 2133443051191. The reversal of 2133443051153 is 3511503443312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1225068221584 + 908374829569 = 1106828^2 + 953087^2 .
It is a cyclic number.
It is not a de Polignac number, because 2133443051153 - 214 = 2133443034769 is a prime.
It is not a weakly prime, because it can be changed into another prime (2133443651153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066721525576 + 1066721525577.
It is an arithmetic number, because the mean of its divisors is an integer number (1066721525577).
Almost surely, 22133443051153 is an apocalyptic number.
It is an amenable number.
2133443051153 is a deficient number, since it is larger than the sum of its proper divisors (1).
2133443051153 is an equidigital number, since it uses as much as digits as its factorization.
2133443051153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 2133443051153 its reverse (3511503443312), we get a palindrome (5644946494465).
The spelling of 2133443051153 in words is "two trillion, one hundred thirty-three billion, four hundred forty-three million, fifty-one thousand, one hundred fifty-three".
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