21341239433 has 2 divisors, whose sum is σ = 21341239434. Its totient is φ = 21341239432.

The previous prime is 21341239429. The next prime is 21341239453. The reversal of 21341239433 is 33493214312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18531921424 + 2809318009 = 136132^2 + 53003^2 .

It is a cyclic number.

It is not a de Polignac number, because 21341239433 - 2² = 21341239429 is a prime.

It is a super-2 number, since 2×21341239433² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21341239393 and 21341239402.

It is not a weakly prime, because it can be changed into another prime (21341239453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10670619716 + 10670619717.

It is an arithmetic number, because the mean of its divisors is an integer number (10670619717).

Almost surely, 2^21341239433 is an apocalyptic number.

It is an amenable number.

21341239433 is a deficient number, since it is larger than the sum of its proper divisors (1).

21341239433 is an equidigital number, since it uses as much as digits as its factorization.

21341239433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 46656, while the sum is 35.

The spelling of 21341239433 in words is "twenty-one billion, three hundred forty-one million, two hundred thirty-nine thousand, four hundred thirty-three".