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213414323331401 is a prime number
BaseRepresentation
bin110000100001100101100100…
…111011101010000101001001
31000222122012200010120120201022
4300201211210323222011021
5210433040013233101101
62033521104153002225
762644450611311003
oct6041454473520511
91028565603516638
10213414323331401
1162000562903305
121bb291610b3375
139210b65b70b4a
143a9b44620d373
1519a15e281ea1b
hexc21964eea149

213414323331401 has 2 divisors, whose sum is σ = 213414323331402. Its totient is φ = 213414323331400.

The previous prime is 213414323331367. The next prime is 213414323331427. The reversal of 213414323331401 is 104133323414312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 213412946995600 + 1376335801 = 14608660^2 + 37099^2 .

It is a cyclic number.

It is not a de Polignac number, because 213414323331401 - 26 = 213414323331337 is a prime.

It is not a weakly prime, because it can be changed into another prime (213414323331301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106707161665700 + 106707161665701.

It is an arithmetic number, because the mean of its divisors is an integer number (106707161665701).

Almost surely, 2213414323331401 is an apocalyptic number.

It is an amenable number.

213414323331401 is a deficient number, since it is larger than the sum of its proper divisors (1).

213414323331401 is an equidigital number, since it uses as much as digits as its factorization.

213414323331401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 62208, while the sum is 35.

Adding to 213414323331401 its reverse (104133323414312), we get a palindrome (317547646745713).

The spelling of 213414323331401 in words is "two hundred thirteen trillion, four hundred fourteen billion, three hundred twenty-three million, three hundred thirty-one thousand, four hundred one".