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2134145131 is a prime number
BaseRepresentation
bin111111100110100…
…0111100001101011
312111201202210202021
41333031013201223
513332320121011
6551434045311
7103612635316
oct17715074153
95451683667
102134145131
119a573a908
124b6879837
132801b4791
1416361797d
15c755e471
hex7f34786b

2134145131 has 2 divisors, whose sum is σ = 2134145132. Its totient is φ = 2134145130.

The previous prime is 2134145087. The next prime is 2134145141. The reversal of 2134145131 is 1315414312.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2134145131 - 217 = 2134014059 is a prime.

It is a super-2 number, since 2×21341451312 = 9109150880342014322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2134145096 and 2134145105.

It is not a weakly prime, because it can be changed into another prime (2134145141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1067072565 + 1067072566.

It is an arithmetic number, because the mean of its divisors is an integer number (1067072566).

Almost surely, 22134145131 is an apocalyptic number.

2134145131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2134145131 is an equidigital number, since it uses as much as digits as its factorization.

2134145131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1440, while the sum is 25.

The square root of 2134145131 is about 46196.8086668333. The cubic root of 2134145131 is about 1287.4824466894.

Adding to 2134145131 its reverse (1315414312), we get a palindrome (3449559443).

The spelling of 2134145131 in words is "two billion, one hundred thirty-four million, one hundred forty-five thousand, one hundred thirty-one".