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213420323131 = 503424294877
BaseRepresentation
bin1100011011000011010…
…1111011000100111011
3202101212121222201220021
43012300311323010323
511444041100320011
6242013254111311
721263516546341
oct3066065730473
9671777881807
10213420323131
1182569232644
123544204b537
13171827c9992
14a4885c1991
155841751471
hex31b0d7b13b

213420323131 has 4 divisors (see below), whose sum is σ = 213844618512. Its totient is φ = 212996027752.

The previous prime is 213420323099. The next prime is 213420323141. The reversal of 213420323131 is 131323024312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 213420323131 - 25 = 213420323099 is a prime.

It is a super-2 number, since 2×2134203231312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 213420323096 and 213420323105.

It is not an unprimeable number, because it can be changed into a prime (213420323141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 212146936 + ... + 212147941.

It is an arithmetic number, because the mean of its divisors is an integer number (53461154628).

Almost surely, 2213420323131 is an apocalyptic number.

213420323131 is a deficient number, since it is larger than the sum of its proper divisors (424295381).

213420323131 is an equidigital number, since it uses as much as digits as its factorization.

213420323131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 424295380.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 213420323131 its reverse (131323024312), we get a palindrome (344743347443).

The spelling of 213420323131 in words is "two hundred thirteen billion, four hundred twenty million, three hundred twenty-three thousand, one hundred thirty-one".

Divisors: 1 503 424294877 213420323131