Base | Representation |
---|---|
bin | 11111000011101010110… |
… | …000101100011001100010 |
3 | 21120000212000121221222002 |
4 | 133003222300230121202 |
5 | 234431412024142010 |
6 | 4312242445444002 |
7 | 310123342115633 |
oct | 37035260543142 |
9 | 7500760557862 |
10 | 2134242412130 |
11 | 753144224a44 |
12 | 2a5769570602 |
13 | 12634834432a |
14 | 7542557188a |
15 | 3a7b34ec1a5 |
hex | 1f0eac2c662 |
2134242412130 has 32 divisors (see below), whose sum is σ = 3852162800640. Its totient is φ = 851358211200.
The previous prime is 2134242412103. The next prime is 2134242412157. The reversal of 2134242412130 is 312142424312.
It is an interprime number because it is at equal distance from previous prime (2134242412103) and next prime (2134242412157).
It is a super-2 number, since 2×21342424121302 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2134242412093 and 2134242412102.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 48099455 + ... + 48143805.
It is an arithmetic number, because the mean of its divisors is an integer number (120380087520).
Almost surely, 22134242412130 is an apocalyptic number.
2134242412130 is a deficient number, since it is larger than the sum of its proper divisors (1717920388510).
2134242412130 is a wasteful number, since it uses less digits than its factorization.
2134242412130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57434.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 2134242412130 its reverse (312142424312), we get a palindrome (2446384836442).
The spelling of 2134242412130 in words is "two trillion, one hundred thirty-four billion, two hundred forty-two million, four hundred twelve thousand, one hundred thirty".
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