Base | Representation |
---|---|
bin | 10011111000001101… |
… | …010101010101111001 |
3 | 2001002111201100002021 |
4 | 103320031111111321 |
5 | 322203043122131 |
6 | 13445542234441 |
7 | 1353632655505 |
oct | 237015252571 |
9 | 61074640067 |
10 | 21344114041 |
11 | 9063217878 |
12 | 4178125a21 |
13 | 2021cb9ba3 |
14 | 1066a0b305 |
15 | 84dc71e11 |
hex | 4f8355579 |
21344114041 has 4 divisors (see below), whose sum is σ = 21347649792. Its totient is φ = 21340578292.
The previous prime is 21344113997. The next prime is 21344114053. The reversal of 21344114041 is 14041144312.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 21344114041 - 217 = 21343982969 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21344113997 and 21344114015.
It is not an unprimeable number, because it can be changed into a prime (21344115041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1758805 + ... + 1770898.
It is an arithmetic number, because the mean of its divisors is an integer number (5336912448).
Almost surely, 221344114041 is an apocalyptic number.
It is an amenable number.
21344114041 is a deficient number, since it is larger than the sum of its proper divisors (3535751).
21344114041 is an equidigital number, since it uses as much as digits as its factorization.
21344114041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3535750.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 21344114041 its reverse (14041144312), we get a palindrome (35385258353).
The spelling of 21344114041 in words is "twenty-one billion, three hundred forty-four million, one hundred fourteen thousand, forty-one".
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