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21344402131 = 1331173306149
BaseRepresentation
bin10011111000001110…
…011011101011010011
32001002112020222021021
4103320032123223103
5322203131332011
613445552340311
71353635265433
oct237016335323
961075228237
1021344402131
1190633a4268
124178244697
13202208b060
141066a842c3
1584dccc471
hex4f839bad3

21344402131 has 16 divisors (see below), whose sum is σ = 23865004800. Its totient is φ = 18956684160.

The previous prime is 21344402111. The next prime is 21344402141. The reversal of 21344402131 is 13120444312.

It is a cyclic number.

It is not a de Polignac number, because 21344402131 - 25 = 21344402099 is a prime.

It is a super-2 number, since 2×213444021312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21344402096 and 21344402105.

It is not an unprimeable number, because it can be changed into a prime (21344402111) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 83356 + ... + 222793.

It is an arithmetic number, because the mean of its divisors is an integer number (1491562800).

Almost surely, 221344402131 is an apocalyptic number.

21344402131 is a deficient number, since it is larger than the sum of its proper divisors (2520602669).

21344402131 is a wasteful number, since it uses less digits than its factorization.

21344402131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 306366.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 21344402131 its reverse (13120444312), we get a palindrome (34464846443).

The spelling of 21344402131 in words is "twenty-one billion, three hundred forty-four million, four hundred two thousand, one hundred thirty-one".

Divisors: 1 13 31 173 403 2249 5363 69719 306149 3979937 9490619 52963777 123378047 688529101 1641877087 21344402131