Base | Representation |
---|---|
bin | 1100011011010111100… |
… | …1000110101111110001 |
3 | 202102002112101222022112 |
4 | 3012311321012233301 |
5 | 11444224242342231 |
6 | 242025522015105 |
7 | 21265565632334 |
oct | 3066571065761 |
9 | 672075358275 |
10 | 213505043441 |
11 | 82602038228 |
12 | 354664a7495 |
13 | 17197220741 |
14 | a49595661b |
15 | 5848dd892b |
hex | 31b5e46bf1 |
213505043441 has 2 divisors, whose sum is σ = 213505043442. Its totient is φ = 213505043440.
The previous prime is 213505043429. The next prime is 213505043459. The reversal of 213505043441 is 144340505312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 164787283600 + 48717759841 = 405940^2 + 220721^2 .
It is a cyclic number.
It is not a de Polignac number, because 213505043441 - 218 = 213504781297 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 213505043398 and 213505043407.
It is not a weakly prime, because it can be changed into another prime (213505049441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106752521720 + 106752521721.
It is an arithmetic number, because the mean of its divisors is an integer number (106752521721).
Almost surely, 2213505043441 is an apocalyptic number.
It is an amenable number.
213505043441 is a deficient number, since it is larger than the sum of its proper divisors (1).
213505043441 is an equidigital number, since it uses as much as digits as its factorization.
213505043441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 213505043441 its reverse (144340505312), we get a palindrome (357845548753).
The spelling of 213505043441 in words is "two hundred thirteen billion, five hundred five million, forty-three thousand, four hundred forty-one".
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