Base | Representation |
---|---|
bin | 110000100011100100111111… |
… | …100010111001000000010011 |
3 | 1001000010021210202221020120211 |
4 | 300203210333202321000103 |
5 | 210442310211032113121 |
6 | 2034104012002344551 |
7 | 62660363126514505 |
oct | 6043447742710023 |
9 | 1030107722836524 |
10 | 213551135035411 |
11 | 62053589508488 |
12 | 1bb4b78305b157 |
13 | 9220a2a031664 |
14 | 3aa3d0421bd75 |
15 | 19a4e4d6a5ce1 |
hex | c2393f8b9013 |
213551135035411 has 2 divisors, whose sum is σ = 213551135035412. Its totient is φ = 213551135035410.
The previous prime is 213551135035397. The next prime is 213551135035507. The reversal of 213551135035411 is 114530531155312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213551135035411 - 29 = 213551135034899 is a prime.
It is not a weakly prime, because it can be changed into another prime (213551135015411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106775567517705 + 106775567517706.
It is an arithmetic number, because the mean of its divisors is an integer number (106775567517706).
Almost surely, 2213551135035411 is an apocalyptic number.
213551135035411 is a deficient number, since it is larger than the sum of its proper divisors (1).
213551135035411 is an equidigital number, since it uses as much as digits as its factorization.
213551135035411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 135000, while the sum is 40.
The spelling of 213551135035411 in words is "two hundred thirteen trillion, five hundred fifty-one billion, one hundred thirty-five million, thirty-five thousand, four hundred eleven".
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