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21356143413603 = 349647114338631
BaseRepresentation
bin1001101101100010111010…
…10101111000100101100011
32210121121221100112212122220
410312301131111320211203
510244344340203213403
6113230513222002123
74332634066603005
oct466613525704543
983547840485586
1021356143413603
1168940a92268a9
12248ab69276343
13bbbb4cb4a96b
1453b8dddd8375
152707c7b66953
hex136c5d578963

21356143413603 has 8 divisors (see below), whose sum is σ = 28474917225216. Its totient is φ = 14237399272200.

The previous prime is 21356143413589. The next prime is 21356143413607. The reversal of 21356143413603 is 30631434165312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 21356143413603 - 213 = 21356143405411 is a prime.

It is not an unprimeable number, because it can be changed into a prime (21356143413607) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5679903 + ... + 8658728.

It is an arithmetic number, because the mean of its divisors is an integer number (3559364653152).

Almost surely, 221356143413603 is an apocalyptic number.

21356143413603 is a deficient number, since it is larger than the sum of its proper divisors (7118773811613).

21356143413603 is a wasteful number, since it uses less digits than its factorization.

21356143413603 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14835105.

The product of its (nonzero) digits is 466560, while the sum is 42.

Adding to 21356143413603 its reverse (30631434165312), we get a palindrome (51987577578915).

The spelling of 21356143413603 in words is "twenty-one trillion, three hundred fifty-six billion, one hundred forty-three million, four hundred thirteen thousand, six hundred three".

Divisors: 1 3 496471 1489413 14338631 43015893 7118714471201 21356143413603