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21360425600113 = 50342466054871
BaseRepresentation
bin1001101101101010111001…
…00101001000010001110001
32210122000222210020111020021
410312311130211020101301
510244432122423200423
6113232502152043441
74333145154564535
oct466653445102161
983560883214207
1021360425600113
1168959a6427a16
12248b963393581
13bbc383071032
1453bbc8a05bc5
15270978a7c95d
hex136d5c948471

21360425600113 has 4 divisors (see below), whose sum is σ = 21402891655488. Its totient is φ = 21317959544740.

The previous prime is 21360425600081. The next prime is 21360425600191. The reversal of 21360425600113 is 31100652406312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21360425600113 - 25 = 21360425600081 is a prime.

It is a super-2 number, since 2×213604256001132 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21360425670113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21233026933 + ... + 21233027938.

It is an arithmetic number, because the mean of its divisors is an integer number (5350722913872).

Almost surely, 221360425600113 is an apocalyptic number.

It is an amenable number.

21360425600113 is a deficient number, since it is larger than the sum of its proper divisors (42466055375).

21360425600113 is an equidigital number, since it uses as much as digits as its factorization.

21360425600113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42466055374.

The product of its (nonzero) digits is 25920, while the sum is 34.

The spelling of 21360425600113 in words is "twenty-one trillion, three hundred sixty billion, four hundred twenty-five million, six hundred thousand, one hundred thirteen".

Divisors: 1 503 42466054871 21360425600113