Base | Representation |
---|---|
bin | 1001101101101100100110… |
… | …10110011011111101010001 |
3 | 2210122010100211022012122120 |
4 | 10312312103112123331101 |
5 | 10244441013142323231 |
6 | 113233133255124453 |
7 | 4333210013221626 |
oct | 466662326337521 |
9 | 83563324265576 |
10 | 21361344495441 |
11 | 6896328095645 |
12 | 248bb7b073729 |
13 | bbc49b552092 |
14 | 53bc74a8034d |
15 | 2709ce58cd96 |
hex | 136d9359bf51 |
21361344495441 has 4 divisors (see below), whose sum is σ = 28481792660592. Its totient is φ = 14240896330292.
The previous prime is 21361344495409. The next prime is 21361344495461. The reversal of 21361344495441 is 14459444316312.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 21361344495441 - 25 = 21361344495409 is a prime.
It is not an unprimeable number, because it can be changed into a prime (21361344495461) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3560224082571 + ... + 3560224082576.
It is an arithmetic number, because the mean of its divisors is an integer number (7120448165148).
Almost surely, 221361344495441 is an apocalyptic number.
It is an amenable number.
21361344495441 is a deficient number, since it is larger than the sum of its proper divisors (7120448165151).
21361344495441 is an equidigital number, since it uses as much as digits as its factorization.
21361344495441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7120448165150.
The product of its digits is 4976640, while the sum is 51.
The spelling of 21361344495441 in words is "twenty-one trillion, three hundred sixty-one billion, three hundred forty-four million, four hundred ninety-five thousand, four hundred forty-one".
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