Base | Representation |
---|---|
bin | 1001101101101110100110… |
… | …01000010110101011110011 |
3 | 2210122020010101210101120211 |
4 | 10312313103020112223303 |
5 | 10300000211110430101 |
6 | 113233431402044551 |
7 | 4333245355415554 |
oct | 466672310265363 |
9 | 83566111711524 |
10 | 21362414545651 |
11 | 6896827104163 |
12 | 24902194a9757 |
13 | bbc60c14789a |
14 | 53bd36c2432b |
15 | 270a434a9c51 |
hex | 136dd3216af3 |
21362414545651 has 4 divisors (see below), whose sum is σ = 21367553451552. Its totient is φ = 21357275639752.
The previous prime is 21362414545643. The next prime is 21362414545663. The reversal of 21362414545651 is 15654541426312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21362414545651 - 23 = 21362414545643 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21362414545595 and 21362414545604.
It is not an unprimeable number, because it can be changed into a prime (21362414545631) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2569446715 + ... + 2569455028.
It is an arithmetic number, because the mean of its divisors is an integer number (5341888362888).
Almost surely, 221362414545651 is an apocalyptic number.
21362414545651 is a deficient number, since it is larger than the sum of its proper divisors (5138905901).
21362414545651 is an equidigital number, since it uses as much as digits as its factorization.
21362414545651 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5138905900.
The product of its digits is 3456000, while the sum is 49.
The spelling of 21362414545651 in words is "twenty-one trillion, three hundred sixty-two billion, four hundred fourteen million, five hundred forty-five thousand, six hundred fifty-one".
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