Base | Representation |
---|---|
bin | 1001101110000100111011… |
… | …01111100011110111111001 |
3 | 2210200101001221121100122112 |
4 | 10313002131233203313321 |
5 | 10300144234330134023 |
6 | 113243133204302105 |
7 | 4334151436132304 |
oct | 467023557436771 |
9 | 83611057540575 |
10 | 21374403755513 |
11 | 68a0919765a66 |
12 | 24926046a1935 |
13 | bc079cca1cc3 |
14 | 53c753233b3b |
15 | 270ee5ce8478 |
hex | 13709dbe3df9 |
21374403755513 has 2 divisors, whose sum is σ = 21374403755514. Its totient is φ = 21374403755512.
The previous prime is 21374403755503. The next prime is 21374403755521. The reversal of 21374403755513 is 31555730447312.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13923622084969 + 7450781670544 = 3731437^2 + 2729612^2 .
It is a cyclic number.
It is not a de Polignac number, because 21374403755513 - 230 = 21373330013689 is a prime.
It is not a weakly prime, because it can be changed into another prime (21374403755503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10687201877756 + 10687201877757.
It is an arithmetic number, because the mean of its divisors is an integer number (10687201877757).
Almost surely, 221374403755513 is an apocalyptic number.
It is an amenable number.
21374403755513 is a deficient number, since it is larger than the sum of its proper divisors (1).
21374403755513 is an equidigital number, since it uses as much as digits as its factorization.
21374403755513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5292000, while the sum is 50.
The spelling of 21374403755513 in words is "twenty-one trillion, three hundred seventy-four billion, four hundred three million, seven hundred fifty-five thousand, five hundred thirteen".
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