Base | Representation |
---|---|
bin | 11111001001000010001… |
… | …011100001011101111011 |
3 | 21120120201120010111021210 |
4 | 133021002023201131323 |
5 | 240030212012432311 |
6 | 4315034305134203 |
7 | 310416203061426 |
oct | 37110213413573 |
9 | 7516646114253 |
10 | 2140004030331 |
11 | 755630537a82 |
12 | 2a68b702a363 |
13 | 126a55c0797b |
14 | 7581084a9bd |
15 | 3a9ee2483a6 |
hex | 1f2422e177b |
2140004030331 has 4 divisors (see below), whose sum is σ = 2853338707112. Its totient is φ = 1426669353552.
The previous prime is 2140004030317. The next prime is 2140004030419. The reversal of 2140004030331 is 1330304000412.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 2140004030331 - 213 = 2140004022139 is a prime.
It is a super-2 number, since 2×21400040303312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2140004030298 and 2140004030307.
It is not an unprimeable number, because it can be changed into a prime (2140004031331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 356667338386 + ... + 356667338391.
It is an arithmetic number, because the mean of its divisors is an integer number (713334676778).
Almost surely, 22140004030331 is an apocalyptic number.
2140004030331 is a deficient number, since it is larger than the sum of its proper divisors (713334676781).
2140004030331 is an equidigital number, since it uses as much as digits as its factorization.
2140004030331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 713334676780.
The product of its (nonzero) digits is 864, while the sum is 21.
Adding to 2140004030331 its reverse (1330304000412), we get a palindrome (3470308030743).
The spelling of 2140004030331 in words is "two trillion, one hundred forty billion, four million, thirty thousand, three hundred thirty-one".
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