214010343313401 has 16 divisors (see below), whose sum is σ = 287522643628800. Its totient is φ = 141587538856320.

The previous prime is 214010343313381. The next prime is 214010343313409. The reversal of 214010343313401 is 104313343010412.

It is not a de Polignac number, because 214010343313401 - 2²² = 214010339119097 is a prime.

It is a super-2 number, since 2×214010343313401² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (214010343313409) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 216537940 + ... + 217524021.

It is an arithmetic number, because the mean of its divisors is an integer number (17970165226800).

Almost surely, 2^{214010343313401} is an apocalyptic number.

It is an amenable number.

214010343313401 is a deficient number, since it is larger than the sum of its proper divisors (73512300315399).

214010343313401 is a wasteful number, since it uses less digits than its factorization.

214010343313401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 434063216.

The product of its (nonzero) digits is 10368, while the sum is 30.

Adding to 214010343313401 its reverse (104313343010412), we get a palindrome (318323686323813).

The spelling of 214010343313401 in words is "two hundred fourteen trillion, ten billion, three hundred forty-three million, three hundred thirteen thousand, four hundred one".