Base | Representation |
---|---|
bin | 111111110001111… |
… | …1000100110011011 |
3 | 12112011000000112211 |
4 | 1333203320212123 |
5 | 13340332111212 |
6 | 552210015551 |
7 | 104014443253 |
oct | 17743704633 |
9 | 5464000484 |
10 | 2140113307 |
11 | 9a9046892 |
12 | 4b88775b7 |
13 | 2814c4147 |
14 | 16432c963 |
15 | c7d3c9a7 |
hex | 7f8f899b |
2140113307 has 2 divisors, whose sum is σ = 2140113308. Its totient is φ = 2140113306.
The previous prime is 2140113301. The next prime is 2140113347. The reversal of 2140113307 is 7033110412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2140113307 - 23 = 2140113299 is a prime.
It is not a weakly prime, because it can be changed into another prime (2140113301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070056653 + 1070056654.
It is an arithmetic number, because the mean of its divisors is an integer number (1070056654).
Almost surely, 22140113307 is an apocalyptic number.
2140113307 is a deficient number, since it is larger than the sum of its proper divisors (1).
2140113307 is an equidigital number, since it uses as much as digits as its factorization.
2140113307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 22.
The square root of 2140113307 is about 46261.3586808689. The cubic root of 2140113307 is about 1288.6814857632.
Adding to 2140113307 its reverse (7033110412), we get a palindrome (9173223719).
The spelling of 2140113307 in words is "two billion, one hundred forty million, one hundred thirteen thousand, three hundred seven".
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