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2140122433 is a prime number
BaseRepresentation
bin111111110001111…
…1010110101000001
312112011000111001211
41333203322311001
513340332404213
6552210130121
7104014512001
oct17743726501
95464014054
102140122433
119a9052729
124b8880941
132814c8347
14164332001
15c7d4053d
hex7f8fad41

2140122433 has 2 divisors, whose sum is σ = 2140122434. Its totient is φ = 2140122432.

The previous prime is 2140122379. The next prime is 2140122443. The reversal of 2140122433 is 3342210412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1893381169 + 246741264 = 43513^2 + 15708^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2140122433 is a prime.

It is not a weakly prime, because it can be changed into another prime (2140122443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070061216 + 1070061217.

It is an arithmetic number, because the mean of its divisors is an integer number (1070061217).

Almost surely, 22140122433 is an apocalyptic number.

It is an amenable number.

2140122433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2140122433 is an equidigital number, since it uses as much as digits as its factorization.

2140122433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

The square root of 2140122433 is about 46261.4573159990. The cubic root of 2140122433 is about 1288.6833175183.

Adding to 2140122433 its reverse (3342210412), we get a palindrome (5482332845).

It can be divided in two parts, 21401 and 22433, that added together give a palindrome (43834).

The spelling of 2140122433 in words is "two billion, one hundred forty million, one hundred twenty-two thousand, four hundred thirty-three".