Base | Representation |
---|---|
bin | 1100011101010000111… |
… | …0100111110100010011 |
3 | 202110102000002200000101 |
4 | 3013110032213310103 |
5 | 12001300041003103 |
6 | 242152222433231 |
7 | 21314315663020 |
oct | 3072416476423 |
9 | 673360080011 |
10 | 214014000403 |
11 | 82843362115 |
12 | 35588a32817 |
13 | 172487c06c8 |
14 | a5033a0547 |
15 | 5878920a1d |
hex | 31d43a7d13 |
214014000403 has 4 divisors (see below), whose sum is σ = 244587429040. Its totient is φ = 183440571768.
The previous prime is 214014000373. The next prime is 214014000407. The reversal of 214014000403 is 304000410412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 214014000403 - 221 = 214011903251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (214014000407) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15286714308 + ... + 15286714321.
It is an arithmetic number, because the mean of its divisors is an integer number (61146857260).
Almost surely, 2214014000403 is an apocalyptic number.
214014000403 is a deficient number, since it is larger than the sum of its proper divisors (30573428637).
214014000403 is an equidigital number, since it uses as much as digits as its factorization.
214014000403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30573428636.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 214014000403 its reverse (304000410412), we get a palindrome (518014410815).
The spelling of 214014000403 in words is "two hundred fourteen billion, fourteen million, four hundred three", and thus it is an aban number.
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