214014015331 has 2 divisors, whose sum is σ = 214014015332. Its totient is φ = 214014015330.

The previous prime is 214014015311. The next prime is 214014015337. The reversal of 214014015331 is 133510410412.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 214014015331 - 2¹³ = 214014007139 is a prime.

It is a super-2 number, since 2×214014015331² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 214014015296 and 214014015305.

It is not a weakly prime, because it can be changed into another prime (214014015337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107007007665 + 107007007666.

It is an arithmetic number, because the mean of its divisors is an integer number (107007007666).

Almost surely, 2^214014015331 is an apocalyptic number.

214014015331 is a deficient number, since it is larger than the sum of its proper divisors (1).

214014015331 is an equidigital number, since it uses as much as digits as its factorization.

214014015331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 214014015331 its reverse (133510410412), we get a palindrome (347524425743).

The spelling of 214014015331 in words is "two hundred fourteen billion, fourteen million, fifteen thousand, three hundred thirty-one".