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214014153 = 371338051
BaseRepresentation
bin11001100000110…
…01100011001001
3112220201001020010
430300121203021
5414241423103
633123022133
75206042653
oct1460314311
9486631203
10214014153
11aa895001
125b80a949
1335452cc2
14205cd6d3
1513bc6903
hexcc198c9

214014153 has 4 divisors (see below), whose sum is σ = 285352208. Its totient is φ = 142676100.

The previous prime is 214014133. The next prime is 214014161. The reversal of 214014153 is 351410412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 214014153 - 29 = 214013641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (214014133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35669023 + ... + 35669028.

It is an arithmetic number, because the mean of its divisors is an integer number (71338052).

Almost surely, 2214014153 is an apocalyptic number.

It is an amenable number.

214014153 is a deficient number, since it is larger than the sum of its proper divisors (71338055).

214014153 is an equidigital number, since it uses as much as digits as its factorization.

214014153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71338054.

The product of its (nonzero) digits is 480, while the sum is 21.

The square root of 214014153 is about 14629.2225699112. Note that the first 3 decimals coincide. The cubic root of 214014153 is about 598.1555888332.

Adding to 214014153 its reverse (351410412), we get a palindrome (565424565).

The spelling of 214014153 in words is "two hundred fourteen million, fourteen thousand, one hundred fifty-three".

Divisors: 1 3 71338051 214014153