Base | Representation |
---|---|
bin | 110000101010011100101011… |
… | …011001001000000110011010 |
3 | 1001001210102101210222201110201 |
4 | 300222130223121020012122 |
5 | 211023024100243142132 |
6 | 2035104530505532414 |
7 | 63036445326034432 |
oct | 6052345331100632 |
9 | 1031712353881421 |
10 | 214023243334042 |
11 | 6221582531890a |
12 | 2000717b1a410a |
13 | 92563c781c50c |
14 | 3abcacd0032c2 |
15 | 19b23808162e7 |
hex | c2a72b64819a |
214023243334042 has 8 divisors (see below), whose sum is σ = 321037595776116. Its totient is φ = 107010711408672.
The previous prime is 214023243334027. The next prime is 214023243334073. The reversal of 214023243334042 is 240433342320412.
It can be written as a sum of positive squares in 2 ways, for example, as 208660596217921 + 5362647116121 = 14445089^2 + 2315739^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×2140232433340423 (a number of 44 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 214023243333992 and 214023243334010.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 454835233 + ... + 455305540.
Almost surely, 2214023243334042 is an apocalyptic number.
214023243334042 is a deficient number, since it is larger than the sum of its proper divisors (107014352442074).
214023243334042 is a wasteful number, since it uses less digits than its factorization.
214023243334042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 910258352.
The product of its (nonzero) digits is 331776, while the sum is 37.
Adding to 214023243334042 its reverse (240433342320412), we get a palindrome (454456585654454).
The spelling of 214023243334042 in words is "two hundred fourteen trillion, twenty-three billion, two hundred forty-three million, three hundred thirty-four thousand, forty-two".
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