Base | Representation |
---|---|
bin | 1100011101010101101… |
… | …1000010001011010001 |
3 | 202110110101210100020221 |
4 | 3013111123002023101 |
5 | 12001320203000223 |
6 | 242154220033041 |
7 | 21314651151124 |
oct | 3072533021321 |
9 | 673411710227 |
10 | 214034031313 |
11 | 828536a3693 |
12 | 35593692781 |
13 | 1724c9b4c0b |
14 | a505cd63bb |
15 | 587a57ab5d |
hex | 31d56c22d1 |
214034031313 has 4 divisors (see below), whose sum is σ = 219818734900. Its totient is φ = 208249327728.
The previous prime is 214034031287. The next prime is 214034031317. The reversal of 214034031313 is 313130430412.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 115106168529 + 98927862784 = 339273^2 + 314528^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-214034031313 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (214034031317) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2892351738 + ... + 2892351811.
It is an arithmetic number, because the mean of its divisors is an integer number (54954683725).
Almost surely, 2214034031313 is an apocalyptic number.
It is an amenable number.
214034031313 is a deficient number, since it is larger than the sum of its proper divisors (5784703587).
214034031313 is an equidigital number, since it uses as much as digits as its factorization.
214034031313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5784703586.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 214034031313 its reverse (313130430412), we get a palindrome (527164461725).
The spelling of 214034031313 in words is "two hundred fourteen billion, thirty-four million, thirty-one thousand, three hundred thirteen".
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