Base | Representation |
---|---|
bin | 1100011101010110010… |
… | …0111011011010111001 |
3 | 202110110120200010020102 |
4 | 3013111210323122321 |
5 | 12001321334000311 |
6 | 242154351405145 |
7 | 21315012203126 |
oct | 3072544733271 |
9 | 673416603212 |
10 | 214036625081 |
11 | 828551053a4 |
12 | 355945237b5 |
13 | 172503b26a6 |
14 | a5063ad74d |
15 | 587a8de43b |
hex | 31d593b6b9 |
214036625081 has 4 divisors (see below), whose sum is σ = 214232810064. Its totient is φ = 213840440100.
The previous prime is 214036625039. The next prime is 214036625107. The reversal of 214036625081 is 180526630412.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 214036625081 - 26 = 214036625017 is a prime.
It is a super-2 number, since 2×2140366250812 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (214026625081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 98090855 + ... + 98093036.
It is an arithmetic number, because the mean of its divisors is an integer number (53558202516).
Almost surely, 2214036625081 is an apocalyptic number.
It is an amenable number.
214036625081 is a deficient number, since it is larger than the sum of its proper divisors (196184983).
214036625081 is a wasteful number, since it uses less digits than its factorization.
214036625081 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 196184982.
The product of its (nonzero) digits is 69120, while the sum is 38.
The spelling of 214036625081 in words is "two hundred fourteen billion, thirty-six million, six hundred twenty-five thousand, eighty-one".
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