Base | Representation |
---|---|
bin | 11111001001011011110… |
… | …001000100101101110001 |
3 | 21120121211110212212122121 |
4 | 133021123301010231301 |
5 | 240032101411220213 |
6 | 4315145042034241 |
7 | 310432634616424 |
oct | 37113361045561 |
9 | 7517743785577 |
10 | 2140433304433 |
11 | 755830887a66 |
12 | 2a69b6948981 |
13 | 126ac3b28a08 |
14 | 758518719bb |
15 | 3aa26c9088d |
hex | 1f25bc44b71 |
2140433304433 has 2 divisors, whose sum is σ = 2140433304434. Its totient is φ = 2140433304432.
The previous prime is 2140433304413. The next prime is 2140433304479. The reversal of 2140433304433 is 3344033340412.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1858946818624 + 281486485809 = 1363432^2 + 530553^2 .
It is a cyclic number.
It is not a de Polignac number, because 2140433304433 - 213 = 2140433296241 is a prime.
It is not a weakly prime, because it can be changed into another prime (2140433304403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070216652216 + 1070216652217.
It is an arithmetic number, because the mean of its divisors is an integer number (1070216652217).
Almost surely, 22140433304433 is an apocalyptic number.
It is an amenable number.
2140433304433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2140433304433 is an equidigital number, since it uses as much as digits as its factorization.
2140433304433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 124416, while the sum is 34.
Adding to 2140433304433 its reverse (3344033340412), we get a palindrome (5484466644845).
The spelling of 2140433304433 in words is "two trillion, one hundred forty billion, four hundred thirty-three million, three hundred four thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •