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2140433304433 is a prime number
BaseRepresentation
bin11111001001011011110…
…001000100101101110001
321120121211110212212122121
4133021123301010231301
5240032101411220213
64315145042034241
7310432634616424
oct37113361045561
97517743785577
102140433304433
11755830887a66
122a69b6948981
13126ac3b28a08
14758518719bb
153aa26c9088d
hex1f25bc44b71

2140433304433 has 2 divisors, whose sum is σ = 2140433304434. Its totient is φ = 2140433304432.

The previous prime is 2140433304413. The next prime is 2140433304479. The reversal of 2140433304433 is 3344033340412.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1858946818624 + 281486485809 = 1363432^2 + 530553^2 .

It is a cyclic number.

It is not a de Polignac number, because 2140433304433 - 213 = 2140433296241 is a prime.

It is not a weakly prime, because it can be changed into another prime (2140433304403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070216652216 + 1070216652217.

It is an arithmetic number, because the mean of its divisors is an integer number (1070216652217).

Almost surely, 22140433304433 is an apocalyptic number.

It is an amenable number.

2140433304433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2140433304433 is an equidigital number, since it uses as much as digits as its factorization.

2140433304433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 124416, while the sum is 34.

Adding to 2140433304433 its reverse (3344033340412), we get a palindrome (5484466644845).

The spelling of 2140433304433 in words is "two trillion, one hundred forty billion, four hundred thirty-three million, three hundred four thousand, four hundred thirty-three".