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21404340313 = 191721654587
BaseRepresentation
bin10011111011110011…
…000101000001011001
32001020201001010222221
4103323303011001121
5322314002342223
613455533144041
71355263614346
oct237363050131
961221033887
1021404340313
119094212754
12419432b021
132031615b35
141070a077cd
158541bbb5d
hex4fbcc5059

21404340313 has 8 divisors (see below), whose sum is σ = 22544010720. Its totient is φ = 20265982560.

The previous prime is 21404340299. The next prime is 21404340371. The reversal of 21404340313 is 31304340412.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21404340313 - 225 = 21370785881 is a prime.

It is not an unprimeable number, because it can be changed into a prime (21404340613) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 294595 + ... + 359992.

It is an arithmetic number, because the mean of its divisors is an integer number (2818001340).

Almost surely, 221404340313 is an apocalyptic number.

It is an amenable number.

21404340313 is a deficient number, since it is larger than the sum of its proper divisors (1139670407).

21404340313 is a wasteful number, since it uses less digits than its factorization.

21404340313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 656327.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 21404340313 its reverse (31304340412), we get a palindrome (52708680725).

Subtracting 21404340313 from its reverse (31304340412), we obtain a palindrome (9900000099).

The spelling of 21404340313 in words is "twenty-one billion, four hundred four million, three hundred forty thousand, three hundred thirteen".

Divisors: 1 19 1721 32699 654587 12437153 1126544227 21404340313