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214105333011953 is a prime number
BaseRepresentation
bin110000101011101001001000…
…010100011001010111110001
31001002002021021210012102122212
4300223221020110121113301
5211030400210222340303
62035210344312341505
763045412513552445
oct6053511024312761
91032067253172585
10214105333011953
116224761a852929
122001b06a9a4895
13926107a869b26
143ac2a794dc825
1519b45874adad8
hexc2ba485195f1

214105333011953 has 2 divisors, whose sum is σ = 214105333011954. Its totient is φ = 214105333011952.

The previous prime is 214105333011929. The next prime is 214105333011959. The reversal of 214105333011953 is 359110333501412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 211561330341904 + 2544002670049 = 14545148^2 + 1594993^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-214105333011953 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 214105333011953.

It is not a weakly prime, because it can be changed into another prime (214105333011959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107052666505976 + 107052666505977.

It is an arithmetic number, because the mean of its divisors is an integer number (107052666505977).

Almost surely, 2214105333011953 is an apocalyptic number.

It is an amenable number.

214105333011953 is a deficient number, since it is larger than the sum of its proper divisors (1).

214105333011953 is an equidigital number, since it uses as much as digits as its factorization.

214105333011953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145800, while the sum is 41.

The spelling of 214105333011953 in words is "two hundred fourteen trillion, one hundred five billion, three hundred thirty-three million, eleven thousand, nine hundred fifty-three".