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2141113200041 is a prime number
BaseRepresentation
bin11111001010000100010…
…010101010110110101001
321120200120212020011002102
4133022010102222312221
5240034444434400131
64315340330343145
7310455531625364
oct37120422526651
97520525204072
102141113200041
1175604a645662
122a6b6658aab5
13126ba19492ca
14758b7c950db
153aa667e11cb
hex1f2844aada9

2141113200041 has 2 divisors, whose sum is σ = 2141113200042. Its totient is φ = 2141113200040.

The previous prime is 2141113200007. The next prime is 2141113200077. The reversal of 2141113200041 is 1400023111412.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2093924761600 + 47188438441 = 1447040^2 + 217229^2 .

It is a cyclic number.

It is not a de Polignac number, because 2141113200041 - 26 = 2141113199977 is a prime.

It is a super-2 number, since 2×21411132000412 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2141113199986 and 2141113200022.

It is not a weakly prime, because it can be changed into another prime (2141113200241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070556600020 + 1070556600021.

It is an arithmetic number, because the mean of its divisors is an integer number (1070556600021).

Almost surely, 22141113200041 is an apocalyptic number.

It is an amenable number.

2141113200041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2141113200041 is an equidigital number, since it uses as much as digits as its factorization.

2141113200041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 2141113200041 its reverse (1400023111412), we get a palindrome (3541136311453).

The spelling of 2141113200041 in words is "two trillion, one hundred forty-one billion, one hundred thirteen million, two hundred thousand, forty-one".